The oxidation number of iodine in the iodate ion (IO –3) is
- -5
- -1
- +1
-
+5
The correct answer is: D
Explanation
1O3[oxidation number of 1] + [oxidation number of 0] x 3 = -1
x + -2 x 3 = 1
x - 6 = - 1
x = - 1 + 6 = +5