The number of sulphur atoms in 3.20g of SO\(_{2(g)}\) is [O = 16.0;S = 32.0; Avogadro constant = 6.02 x 10\(^{23}\)]
-
3.01 x 1022
- 6.02 x 1022
- 6.02 x1023
- 1.20 x 1024
The correct answer is: A
Explanation
32g of sulphur = 64g / 6.02 x 10\(^{23}\) atoms of SO\(_2\)
xg of sulphur = 3.2g of SO\(_2\)
: 1.6g of sulphur is present in 3.2g / 3.01 x 10\(^{23}\) atoms of SO\(_2\)