The volume occupied by 0.4 g of hydrogen gas at s.t.p. is [H = 1. 00; Molar volume at s.t.p. = 22.4 dm3]
- 2.24 dm3
-
4.48dm3
- 22.4dm3
- 44.8dm 3
The correct answer is: B
Explanation
2g of H\(_2\) = 22.4 dm\(^3\)
0.4g of H\(_2\) = x,
x = \(\frac{0.4 \times 22.4}{2}\) = 4.48dm\(^3\)