The percentage by mass of calcium in Ca(OCI)2 is [Ca = 40.0; CI = 35.5; O = 16.0]
-
28.0%
- 31.6%
- 43.8%
- 44.5%
The correct answer is: A
Explanation
Molar mass of \(Ca(OCl)_2\) = 40 + (16 + 35.5)x2 = 143
% by mass of calcium in the compound =\(\frac{mass of calcuim}{molar mass of compound}\) x 100%
% calcium = \(\frac{40}{143} \times100\)
= 27.98% = 28%