The number of oxygen molecules present in 16.0g of the gas is ______?
[Avogadro’s number = 6.02 x 1023]
- 6.02 x 1022
- 6.02 x 1023
-
3.01 x 1023
- 1.51 x 1023
The correct answer is: C
Explanation
1 mole = Molar mass of gas = Avogadros number32g of O2 = 6.02 x 1023
16g of O2 = x
x = \(\frac{16 \times 6.02 \times 10^23}{32}\) = 3.01 x 1023