Consider the following reaction equation:
SO42-(aq) + 2H+(aq) + ye– \(\to\) SO42-(aq) + H2O(1).
The value of y in the equation is
-
2
- 3
- 4
- 6
The correct answer is: A
Explanation
from the reaction, the total charge on the left side = The total charge on the right side-2 + 2 + y = -2 : y = -2 : y = 2