A compound has an empirical formular CH2O and molecular mass of 90.
[H = 1.00, C = 12.0, O = 16.0]
The correct answer is: C
Explanation
(CH2O)n = 90; (12 + (1 x 2) + 16)n = 90(12 + 2 + 16)n = 90; 30n = 90; n = \(\frac{90}{30}\); n = 3
(CH2O)3 = Molecular formula ; = C3H6O3