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How many electrons are present in \(^9_4Be^{2+}\)?

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Chemistry WAEC 2016

How many electrons are present in \(^9_4Be^{2+}\)?

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The correct answer is: A

Explanation

Neutral Be has 4 electrons but \(Be^{2+}\) means it has lost two electrons from possible four and became a positive ion. 

\(\therefore\) the number of electrons left will be equal to two.

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