How many moles of oxygen would contain 1.204 x 1024 molecules?
[Avogadro’s constant (NA) = 6.02 x 1023]
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The correct answer is: B
Explanation
6.02 x 1023 molecules is 1mole1.204 x 1024 molecules will be......
\(\frac{1.204 \times 10^24 \times 1}{6.02 \times 10^23}\)
\(\frac{1.204 \times 10}{6.02}\) = \(\frac{12.04}{6.02}\) = 2moles