The mass of one mole of \((NH_{4})_{2}CO_{3}\) is [O=16.0, N=14.0, C=12.0, H=1.0]
- 66.0g
- 76.0g
- 80.0g
-
96.0g
The correct answer is: D
Explanation
This is same as asking for the molar mass of the compound
= \((2\times 14.0)+ (8\times 1.0) + 12.0+(16.0\times 3)\)
= 28.0+8.0+12.0+48.0 = 96.0g