The number of atoms present in 2.5moles of a triatomic gas is equivalent to [1mole = \(6.02\times 10^{23}\)]
- \(2.5\times 10^{23}\)
- \(1.5\times 10^{23}\)
-
\(1.5\times 10^{24}\)
- \(2.5\times 10^{24}\)
The correct answer is: C
Explanation
1 mole = \(6.02 \times 10^{23}\)
2.5 moles = \(6.02 \times 10^{23} \times 2.5\)
= \(15.05 \times 10^{23} = 1.505 \times 10^{24}\)
\(\approxeq 1.5 \times 10^{24}\)