A hydrocarbon contained 14.3% hydrogen. The empirical formula for the hydrocarbon is [H= 1.0, C= 12.0]
- \(CH\)
-
\(CH_{2}\)
- \(CH_{3}\)
- \(CH_{4}\)
The correct answer is: B
Explanation
The percentage of Carbon in the compound is (100 - 14.3)% = 85.7%
C : H
\(\frac{85.7}{12.0} : \frac{14.3}{1.0}\)
\( 7.14 : 14.3\)
\(\frac{7.14}{7.14} : \frac{14.3}{7.14}\)
\(\approxeq 1 : 2\)
Therefore, the empirical formula is \(CH_{2}\).