Consider the following reaction equation: \(2NO_{(g)} + O_{{2}{(g)}} \to 2NO_{{2}{(g)}}\). What is the change in the oxidation number of nitrogen?
- +2 to 0
- +2 to -2
-
+2 to +4
- +4 to +2
The correct answer is: C
Explanation
In NO, the oxidation number for nitrogen is N - 2 = 0
⇒ N = +2
In \(NO_{2}\), we have N - (2x2) =0
N - 4 =0
N =+4