What is the solubility of a salt if 0.4g of it is obtained on evaporating 200\(cm^{3}\) of its saturated solution to dryness?
- 0.08\(gdm^{-3}\)
-
2.00\(gdm^{-3}\)
- 8.00\(gdm^{-3}\)
- 80.00\(gdm^{-3}\)
The correct answer is: B
Explanation
1000\(cm^{3}\) = 1\(dm^{3}\)
200\(cm^{3}\) = 0.2\(dm^{3}\)
⇒ 0.2\(dm^{3}\) contains 0.4g
hence, solubility of the salt which is the amount of the salt dissolvable in 1\(dm^{3}\) is
\(\frac{0.4g}{0.2dm^{3}} = 2.0gdm^{-3}\)