What is the solubility of a salt X at 25ºC if the saturated solution of the salt contains 0.28g in 100cm\(^3\) of the solution in mol\dm\(^3\)?
[ X = 56.0g ]
-
0.05
- 0.10
- 2.60
- 2.80
The correct answer is: A
Explanation
(mass / molar mass) X (1000 / vol )
(0.28 / 56.0) X (1000 / 100 )
= 2.8 / 56
= 0.05 mol\dm\(^3\)