An organic compound contains 72% carbon, 12% hydrogen and 16% oxygen by mass. What is the empirical formula of the compound?
[ H = 1.0. C = 12.0, O = 16.0 ]
- C\(_3\)H\(_8\)O
-
C\(_6\)H\(_{12}\)O
- C\(_6\)H\(_{12}\)O\(_2\)
- C\(_{12}\)H\(_{12}\)O\(_{11}\)
The correct answer is: B
Explanation
C = 72 / 12 H = 12 / 1 O = 16 / 16
C = 6 H = 12 O = 1
: EMPIRICAL FORMULA
C\(_6\)H\(_{12}\)O