The oxidation of chromium in Cr\(_2\)O\(_7)\(-2\) ?
The correct answer is: C
Explanation
2 atoms of Cr,
7 X -2 atoms of O
2Cr - 14 = -2
2Cr = -2 + 14
2Cr = 12
Cr = 6
The oxidation of chromium in Cr\(_2\)O\(_7)\(-2\) ?
2 atoms of Cr,
7 X -2 atoms of O
2Cr - 14 = -2
2Cr = -2 + 14
2Cr = 12
Cr = 6