consider the reaction represented by the following equation: 2SO\(_2\) + O\(_2\) ⇌ 2SO\(_3\)
A decrease in the pressure of the reaction would
- decrease in the concentration of SO\(_2\)
- have no effect on the reaction
-
shift the equilibrium position to the left
- shift the equilibrium position to the right
The correct answer is: C
Explanation
decrease in pressure favors the side with higher volume thus the equilibrium position will shift to the left