f 5.0 cm\(^-3\) of 0.200 mol dm(^-3\) Na\(_2\)CO\(_3\) was diluted to 250cm(^-3\) solution, what would be the concentration of the resulting solution?
-
0.004 mol dm(^-3\)
- 0.020 mol dm(^-3\)
- 0.200 mol dm(^-3\)
- 0.400 mol dm(^-3\)
The correct answer is: A
Explanation
 |
= | initial molarity |
 |
= | initial volume in liters |
 |
= | |
 |
= | final volume in liters |
0.200 X 5.00 = M\(_2\) X 250
M\(_2\) = 1 / 250
M\(_2\) = 0.004 mol dm(^-3\)