How many moles of H\(_2\)SO4 are there in 50 cm\(^3\) of 0.108 mol dm\(^3\) solution of the acid?
- 5.4x 10
-
5.4 x 10\(^{-3}\)
- 5.4 x 10\(^{-2}\)
- 5.4x 10\(^{-1}\)
The correct answer is: B
Explanation
No. of moles = \(\frac{molar conc \times volume}{1000}\)
No. of moles = \(\frac{0.108 \times 50}{1000}\)
: No. of moles = 0.0054 moles = \( 5.4 \times 10^{-3}\)