. If 20 cm\(^3\) of sodium hydroxide was neutralized by 20 cm\(^3\) of 0.01 mol dm3 tetraoxosulphate(VI) acid, what is the concentration of the solution?
- 0.010
-
0.020
- 0.100
- 0.150
The correct answer is: B
Explanation
\(frac{CaVa}{CbVb}\) = \(frac{Na}{Nb}\)
( 0.01 X 20 ) / (Cb X 20) = 1 / 2
cross multiply → Cb = (0.01 X 20 X 2) / ( 20 X 1)
Cb = 0.02 mol/dm\(^3\)