If the molar mass of X(HCO3)\(_{2}\) is 162 g mol\(^{-1}\), determine the relative atomic mass of X.
[H = 1.0, C = 12.0, 0 = 16.0]
-
40
- 48
- 61
- 101
The correct answer is: A
Explanation
Molar mass of X(HCO3)2 = X+(1+12+(16*3))2=162
=X + (13+48)2=162
X + 122=162
X=162-122
X=40