Convert \(47_8\) to its binary equivalent.
The correct answer is: A
Explanation
Convert to base 10 first.
\(47_8\) = 4 x \(8^1\) + 7 x \(8^0\) = \(39_{10}\)
Then convert \(39_{10}\) to base 2 as follows
2 | 39 |
2 | 19 R 1 |
2 | 9 R 1 |
2 | 4 R 1 |
2 | 2 R 0 |
2 | 1 R 0 |
2 | 0 R 1 |
Therefore \(47_8\) is equivalent to \(100111_2\)