Find the number of different arrangements of the word IKOTITINA.
The correct answer is: A
Explanation
IKOTITINA has 9 letters with 2Ts and 3Is. Therefore, the number of different arrangements
= \(\frac{9!}{2!3!} = \frac{9.8.7.6.5.4}{2} = 30240\)
Find the number of different arrangements of the word IKOTITINA.
IKOTITINA has 9 letters with 2Ts and 3Is. Therefore, the number of different arrangements
= \(\frac{9!}{2!3!} = \frac{9.8.7.6.5.4}{2} = 30240\)