Express \(\log \frac{1}{8} + \log \frac{1}{2}\) in terms of \(\log 2\).
- 3 log 2
- 4 log 2
- -3 log 2
-
-4 log 2
The correct answer is: D
Explanation
\(\log \frac{1}{8} + \log \frac{1}{2} = \log 8^{-1} + \log 2^{-1}\)
= \(\log 2^{-3} + \log 2^{-1}\)
= \(-3 \log 2 - 1 \log 2 = -4 \log 2\)