A particle accelerates at 12\(ms^{-2}\) and travels a distance of 250m in 6 seconds. Find the initial velocity of the particle.
-
5.7\(ms^{-1}\)
- 6.0\(ms^{-1}\)
- 60.0\(ms^{-1}\)
- 77.5\(ms^{-1}\)
The correct answer is: A
Explanation
\(s = ut + \frac{1}{2}at^{2}\)
\(250 = 6u + \frac{1}{2}(12)(6^{2})\)
\(250 = 6u + 216 \implies 6u = 250 - 216 = 34\)
\(u = \frac{34}{6} \approxeq 5.7ms^{-1}\)