A ball is thrown vertically upwards with a velocity of 15\(ms^{-1}\). Calculate the maximum height reached. \([g = 10ms^{-2}]\)
- 15.25m
- 13.25m
-
11.25m
- 10.25m
The correct answer is: C
Explanation
Maximum height (H) = \(\frac{u^{2}}{2g}\)
= \(\frac{15^{2}}{2 \times 10} = \frac{225}{20}\)
= \(11.25m\)