The sum, \(S_{n}\), of a sequence is given by \(S_{n} = 2n^{2} – 5\). Find the 6th term.
- 112
- 67
- 45
-
22
The correct answer is: D
Explanation
\(S_{n} = 2n^{2} - 5\)
\(T_{n} = S_{n} - S_{n - 1}\)
\(T_{6} = S_{6} - S_{5}\)
= \((2(6^{2} - 5) - (2(5^{2} - 5) = 62 - 40 = 22\)