If (2t – 3s)(t – s) = 0, find \(\frac{t}{s}\).
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\(\frac{3}{2}\) or \(1\)
- \(\frac{3}{2}\) or \(-1\)
- \(\frac{-3}{2}\) or \(-1\)
- \(\frac{-3}{2}\) or \(1\)
The correct answer is: A
Explanation
\((2t - 3s)(t - s) = 0 \implies (2t - 3s) = \text{0 or} (t - s) = 0\)
\(2t - 3s = 0 \implies 2t = 3s \therefore \frac{t}{s} = \frac{3}{2}\)
\(t - s = 0 \implies t = s \therefore \frac{t}{s} = 1\)
\(\frac{t}{s} = \frac{3}{2} or 1\)