Given n = 3, evaluate \(\frac{1}{(n-1)!} – \frac{1}{(n+1)!}\)
- \(12\)
- \(2\frac{1}{2}\)
- \(2\)
-
\(\frac{11}{24}\)
The correct answer is: D
Explanation
n = 3, \(\frac{1}{(n-1)!} - \frac{1}{(n+1)!} = \frac{1}{(3-1)!} - \frac{1}{(3+1)!}\)
= \(\frac{1}{2} - \frac{1}{24} = \frac{12 -1}{24}\)
= \(\frac{11}{24}\)