Simplify \(\frac{\sqrt{128}}{\sqrt{32} – 2\sqrt{2}}\)
- \(2\sqrt{2}\)
- \(3\sqrt{2}\)
- 3
-
4
The correct answer is: D
Explanation
\(\sqrt{128} = \sqrt{64\times2} = 8\sqrt{2}\)
\(\sqrt{32} = \sqrt{16\times2} = 4\sqrt{2}\)
Simplifying, we have \(\frac{8\sqrt{2}}{4\sqrt{2} - 2\sqrt{2}} = \frac{8\sqrt{2}}{2\sqrt{2}}\)
= 4