Given that \(m = 3i – 2j ; n = 2i – 3j\) and \(p = -i + 6j\), find \(4m + 2n – 3p\).
\(m = 3i - 2j ; n = 2i - 3j ; p = -i + 6j\)
\(4m + 2n - 3p = 4(3i - 2j) + 2(2i - 3j) - 3(-i + 6j)\)
= \(12i - 8j + 4i - 6j + 3i - 18j\)
= \(19i - 32j\)
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