If \(\frac{6x + k}{2x^2 + 7x – 15}\)  = \(\frac{4}{x + 5} – \frac{2}{2x -…

Further Mathematics WAEC 2020

If \(\frac{6x + k}{2x^2 + 7x – 15}\)  = \(\frac{4}{x + 5} – \frac{2}{2x – 3}\). Find the value of k. 

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The correct answer is: B

Explanation

\(\frac{6x + k}{2x^2 + 7x - 15} = \frac{4}{x + 5} - \frac{2}{2x - 3}\)

6x + k = 4 (2x - 3) - 2(x + 5)

6x + k = 8x - 12 - 2x - 10 

6x + k = 6x - 22 

k = - 22 

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