P(3,4) and Q(-3, -4) are two points in a plane. Find the gradient of the line that is normal to the line PQ.
- \(\frac{4}{3}\)
-
\(\frac{3}{4}\)
- \(\frac{-3}{4}\)
- \(\frac{-4}{3}\)
The correct answer is: B
Explanation
Gradient = \(\frac{-4 - 4}{-3 - 3}\)
= \(\frac{-8}{6}\)
= \(\frac{4}{3}\)
Normal = -(\(\frac{1}{\frac{1}{4}}\))
= \(\frac{-3}{4}\)