Simplify \(\frac{1}{3}\) log8 + \(\frac{1}{3}\) log 64 – 2 log6
- log \(\frac{2}{7}\)
- log 2
-
log \(\frac{2}{9}\)
- log 9
The correct answer is: C
Explanation
\(\frac{1}{3}\) log8 + \(\frac{1}{3}\) log 64 - 2 log6
= log 2 + log 4 - log 36
= log \(\frac{8}{36}\)
= log \(\frac{2}{9}\)