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If f(x) = 4x\(^3\) + px\(^2\) + 7x – 23 is divided by (2x -5),…

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Further Mathematics WAEC 2021

If f(x) = 4x\(^3\) + px\(^2\) + 7x – 23 is divided by (2x -5), the remainder is 7. find the value of p

  • -7.0
  • -8.0 checkmark
  • -9.6
  • 9

The correct answer is: B

Explanation

f(x) = 4x\(^3\) + px\(^2\) + 7x - 23

If f(x) is divided by (2x -5), the remainder is f(\(\frac{5}{2}\))

f\(\frac{5}{2}\) = 4\(\frac{5}{2}\)\(^3\) + p\(\frac{5}{2}\)\(^2\) + 7\(\frac{5}{2}\) - 23

Hence;

 = \(\frac{125}{8}\) + \(\frac{25}{4}\) p + \(\frac{35}{2}\) - 23

28 = 250 + 250p + 70 - 92

25p = -200;  p = -8.0

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