Evaluate \(∫^0_{-1}\) (x + 1)(x – 2) dx
- 7/6
- 5/6
- -5/6
-
-7/6
The correct answer is: D
Explanation
\(∫^0_{-1}\) (x + 1)(x - 2) dx
= \(∫^0_{-1}\) \(x^2 - x - 2\) dx
Integrated \(x^2 - x - 2\) = \(\frac{x^3}{3} - \frac{x^2}{2} -2\)
| = | (0 | - | 0 | - | 0) | - | ( | -1
3 |
- | 1
2 |
+ | 2) |
| = | 0 | - | ( | 7
6 |
) | = | -7
6 |