A particle moving with a velocity of 5m/s accelerates at 2m/s\(^2\). Find the distance it covers in 4 seconds.
- 16m
- 26m
-
36m
- 46m
The correct answer is: C
Explanation
from the equation of motion
u = 5m/s, a = 2m/s\(^2\), t = 4s
s = ut + \(\frac{1}{2} at^2\)
s = 5*4 + \(\frac{1}{2} 2*4^2\)
s = 20 + 16
s = 36m