A particle of mass 3kg moving along a straight line under the action of a F N, covers a line distance, d, at time, t, such that d = t\(^2\) + 3t. Find the magnitude of F at time t.
- 0N
- 2N
- 3(2t + 3)N
-
6N
The correct answer is: D
Explanation
F = m * a
d = t\(^2\) + 3t.
a = \(\frac{d^2d}{dt^2}\)
\(\frac{d[d]}{dt}\) = 2t + 3
\(\frac{d^2d}{dt^2}\) = 2m/s\(^2\)
a = 2m/s\(^2\)
F = m * a
F = 3 × 2 = 6N