If f(x-1) = x\(^3\) + 3x\(^2\) + 4x – 5, find f(2)
The correct answer is: A
Explanation
x - 1 = 2
x = 3
f(2) = (3)\(^3\) + 3(3)\(^2\) + 4(3) - 5
f(2) = 27 + 27 + 12 - 5
= 61
If f(x-1) = x\(^3\) + 3x\(^2\) + 4x – 5, find f(2)
x - 1 = 2
x = 3
f(2) = (3)\(^3\) + 3(3)\(^2\) + 4(3) - 5
f(2) = 27 + 27 + 12 - 5
= 61