In how many ways can four Mathematicians be selected from six ?
The correct answer is: C
Explanation
\(=^6C_4\)
\(=\frac{6!}{(4!\times2!)}\)
\(=\frac{6\times5}{2\times1}\)
= 15
In how many ways can four Mathematicians be selected from six ?
\(=^6C_4\)
\(=\frac{6!}{(4!\times2!)}\)
\(=\frac{6\times5}{2\times1}\)
= 15