If 5x + 7 \(\equiv\) P(x + 3) + Q(x – 1), find the value of p
-
3
- 2
- 1
- 0
The correct answer is: A
Explanation
5x + 7 \(\equiv\) P(x + 3) + Q(x - 1),
Put x = 1
5(1) + 7 \(\equiv\) P(1 + 4) + Q(1 - 1)
12 \(\equiv\) 4p + 0
P = \(\frac{12}{4}\) = 3