If kx\(^2\) is a term in the binomial expansion of (1 – 2x)\(^4\), find the value of k.
- -24
- -8
- 8
-
24
The correct answer is: D
Explanation
Given: (1 - 2x)\(^4\), find kx\(^2\)
Using, \(^4_rCr(-2x)^r(1)^r\)
Where r is from x\(^2\) = 2
\(^4_2Cr(-2x)^2(1)^2\) = 6 * 4x\(^2\) = 24x\(^2\)
kx\(^2\) = 24x\(^2\)
Therefore, k = 24.