A body of mass 42 kg increases its speed from 15 ms\(^{-1}\) to 43 ms\(^{-1}\) in 12 seconds. Find the force acting on the body.
- 203N
- 150N
-
98N
- 52N
The correct answer is: C
Explanation
Using F = \(\frac{M(u_2 - u_1)}{t}\)
F = \(\frac{42 (43 - 15)}{12}\) = \(\frac{42 \times 28}{12}\) = \(\frac{1176}{12}\) = 98N