Given that f(x) = x\(^2\) + 3x + 1, find the value of x at the turning point.
- 2
- 1\(\frac{1}{2}\)
-
-1\(\frac{1}{2}\)
- -2
The correct answer is: C
Explanation
Given that f(x) = x\(^2\) + 3x + 1
At turning point f"(x) = 0
f" = 2x + 3 = 0
= 2x = -3
x = \(\frac{-3}{2}\) = -1\(\frac{1}{2}\)