Find x in the diagram below.
- A. 3\(\sqrt{3}\)
- B. \(\frac{3(\sqrt{3} - 1)}{\sqrt{3} + 1}\)
- C. \(\frac{(\sqrt{3} - 1)}{\sqrt{3} + 1}\)
- D. \(\frac{3 - 1}{\sqrt{3} + 1}\)
PQ is parallel to RS. Calculate the value of x.
- A. 20o
- B. 40o
- C. 60o
- D. 80o
- E. 100o
In the parallelogram PQRS, PE is perpendicular to QR. Find the area of the parallelogram.
- A. 60cm2
- B. 65cm2
- C. 72cm2
- D. 132cm2
- E. 156cm2
(Numbers indicate the lengths of the sides of the triangles) If the area of \(\bigtriangleup\) PQR is k2sq. units what is the area of the shades portion?
- A. \(\frac{5}{9}\)k2 sq. units
- B. \(\frac{1}{3}\)k2 sq. units
- C. \(\frac{8}{9}\)k2 sq. units
- D. \(\frac{7}{9}\)k2 sq. units
- E. \(\frac{2}{3}\)k2 sq. u
In the figure, PQ is parallel to SQ ; QS bisets < PSQ, < PQS is 65o and < RPS is 20o. What is the size of < PRS?
- A. 45o
- B. 35o
- C. 40o
- D. 30o
- E. 42o
In the figure, PQ and QR are chords of the circle PQR. QRS is a straight line and PR is equal to RS, < PSR is 20o. What is the size of <POQ.
- A. 70o
- B. 90o
- C. 80o
- D. 40o
- E. 60o
If O is the centre of the circle, < POS equls
- A. 70o
- B. 75o
- C. 105o
- D. 140o
- E. 150o
In this figure, PQRS is a parallelogram, PS = PT and < PST = 55\(^o\). The size of <PQR is
- A. 125o
- B. 120o
- C. 115o
- D. 110o
- E. 10o
In the figure, \(\bigtriangleup\) ABC are in adjacent planes. AB = AC = 5cm, BC = 6cm and
- A. 3\(\sqrt{2}\)
- B. 2\(\sqrt{3}\)
- C. \(\frac{\sqrt{3}}{2}\)
- D. \(\frac{2}{\sqrt{3}}\)