PQRS is a cyclic quadrilateral with PQ as diameter of the circle. If < PQS = 15o find < QRS
- 75o
- 37\(\frac{1}{2}\)o
- 127\(\frac{1}{2}\)o
-
105o
The correct answer is: D
Explanation
PSO = 90o(angle in a semicircle)SPO = 180o - (90o + 15o) = 75o
< QRS = 108o - 75o
= 105o(opposite angles in cyclic quadrilateral are supplementary)