In the figure, If PT is parallel to RS, PQ = PT, and angle SQT = 90o, Find x
- 35o
- 50o
- 55o
-
70o
- 80o
The correct answer is: D
Explanation
from the diagram above, angle b = 180º - 55º - x ( 55º not 56º)
sum of angle at Q = y + 90º + 180º - 55º - x = 180º( sum of angles on a straight line)
y - x = -35 ..................................... eq1
sum of angle in triangle TPQ = 180º - x + 2y = 180º ( sum of angles in a triangle )
2y - x = 0 ............................................eq2
solving eq1 and eq 2 simultaneously
x = 70º