In the figure, FGHJ is a circle of radius 3cm centre O. FOH, GOJ are perpendicular diameters. With G as centre of an arc of a circle is drawn to pass through F and H. Find the length of the perimeter of the lunar portion shaded.
- 3\(\pi\)\(\sqrt{2 - 1}\)cm
- \(\frac{9}{2}\)\(\pi\)cm
-
3 \(\pi\)(1 + \(\frac{2}{2}\))
- 3(1 + \(\frac{2}{2}\))
The correct answer is: C
Explanation
Perimeter of lunar portion = 3\(\pi\) + \(\frac{3\pi \sqrt{2}}{2}\)= 3 \(\pi\)(1 + \(\frac{2}{2}\))