Which of the formula below represents the general terms of the following set of numbers(-1, \(\frac{2}{3}\), -\(\frac{1}{2}\), \(\frac{2}{5}\)……) for n = 1, 2, 3, 4…….?
- \(\frac{2}{n + 1}\)
- (-1)n + 1 \(\frac{2}{n + 1}\)
-
(-1)n \(\frac{2}{n + 1}\)
- \(\frac{n}{2n - 1}\)
- (-1)n\(\frac{n}{2n - 1}\)
The correct answer is: C
Explanation
(-1, \(\frac{2}{3}\), -\(\frac{1}{2}\), \(\frac{2}{5}\)......)nthterm is (-1)n\(\frac{2}{n + 1}\)
Since (-1)n will always be negative for n = odd